With the popularization of smart phones and other products, developed countries such as Europe, America and Japan have special regulations on the safety and safety of charger products. There are hidden safety hazards in charger products. Regardless of any abnormality that causes the charger to melt the shell or cause a fire accident, take The principle of zero tolerance
In early 2012, Huawei formulated a series of requirements for semi-short circuit resistors to prevent the occurrence of similar phenomena in the molten shell and avoid fire accidents.
一、The main reasons that cause the charger to melt the shell are as follows：
- 1Use ordinary wire-wound fuse resistor, no protection function；
- 2The environment of the charger during use is harsh, which causes the internal components of the charger to be damp and short-circuit. Because the ordinary wire-wound fuse resistor is not used for protection, the charger is finally melted.；
- 3The quality of the internal components selected by the charger is unstable, and ordinary wire-wound fuse resistors have no protection function, which causes the charger to melt the shell；
二、Description：
- 1Use ordinary wire-wound fuse resistors. For example, when the charger is in use, the abnormality does not provide protection function. Explain: In the early days, most power supply manufacturers used ordinary wire-wound fuse resistors, and they have been pursuing strong lightning, pulse resistance, and strong resistance. Voltage, and most of the wire-wound fuse resistors manufactured by resistance factories, in accordance with the national standard "GB9364.4-2006-IEC 60127- 41996 Small Fuses Part 4 General Modular Fuse-links", judgment: blown Current and time, for example: 1WS 10R J is calculated according to the ohm formula = 1.58A is the fusing current, and the resistance is fused within 30 seconds. The normal working current of the resistor is 316mA. Any abnormality of the internal components of the charger may cause ordinary The wire-wound fuse resistor is overloaded, and the ordinary wire-wound fuse resistor continues to glow red, and finally the charger shell is melted and deformed and melted through the shell. In severe cases, a fire accident may occur.。
- 2Common case description: Use ordinary wire-wound fuse resistor 1W, fusing current is 1.58A, normal working current is 316mA, such as aluminum electrolytic capacitors with unstable quality and leakage The solution is generally above 600mA current. Ordinary wire-wound fuse resistors have to withstand more than 600mA current. If they continue to work under overloaded conditions, they will definitely turn red and finally melt the shell. You can simulate this test to verify
- The quality of the internal components selected by the charger is unstable, and ordinary wire-wound fuse resistors do not have a protective function, which causes the charger to melt;
